Question

Please answer the question its urgent​

Answer 1

Answer:

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Explanation:

Let the initial velocity be and acceleration be

Case 1 :

Distance covered S = 20m

Time taken t = 1s

Using S = ut + 1 at^2

2

Or 20 = u(1) + 1 a(1)^2

2

20 = u + a

2

We get u = 20 - a

2

Case 2 :

Total distance covered

S = 20 + 40 = 60m

Total time taken

t = 1 + 1 = 2s

So, 60 = u(2) + 1 a(2)^2

2

or 60 = 2u + 2a

60 = 2(20 - a/2) + 2a

60 = 40 - a + 2a

a = 60 - 40

a = 20m/s-2