Question

please answer the question no.37 and please don't spam or else your answer will be reported​

Answer 1

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Answer 2

Answer:

Explanation:

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Given:-

l = 3.25 m, W = 250 N, μ=0.3

let Ff be the frictional force acting on the ladder at the point of contact between the ladder and floor.

Rf = 250 N

BC=(3.25)2−1.252−−−−−−−−−−−−−√=3 mtaking moments about B and equating the samewe

getFf×3=(Rf×1.25)−(250×0.625)=156.2

NFf=156.2/3=52.1 N