Question

please answer the question no 4

Answer 1

Hey mate!!!

In ∆ PRT,
<P+<R+<T= 180°( from all the angle property of ∆).
=> 95°+40°+<T= 180°
=> 135°+<T= 180°
=> <T= 180°-135°
=> <T= 45°

In ∆ SQT,
<S+<Q+<T= 180°( by all angle property of ∆).
=> 75°+ <Q+45°=180°
=> 120°+<Q= 180°
=> <Q= 180°-120°
=> <Q= 60°
Or <SQT= 60°


Hope it helps you.....
Be brainly

Answer 2

In triangle PQT
anglePRT +angle RPT+angle PTR= 180°
40+95 +angle PTR=180
angle PTR=180-135
= 45
angle PTR=angle STQ (v.o angle)
In ∆STQ
angle STQ +angle TSQ+angle SQT=180°
45+75+angle SQT=180
angle SQT=180-120
=60°
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