Please answer the question no. 7
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as<PRA=35°
angle PQR=35°
Angle PRQ=90°(as the angle inscribed inside a semicircle is always 90°)
angle QPR=180°-(90°+35°)=55°
so angle QRB=55°
Hope you understand this......☺☺☺
as<PRA=35°
angle PQR=35°
Angle PRQ=90°(as the angle inscribed inside a semicircle is always 90°)
angle QPR=180°-(90°+35°)=55°
so angle QRB=55°
Hope you understand this......☺☺☺
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