Physics, asked by keerthyreddy7788, 5 hours ago

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Answered by Aarsal
37

Given That : initial velocity u = 10 m/s.

➛Final velocity v = 20 m/s.

➛Distance travelled = s = 135 m.

➛From the equation of motion,v = u + at.

Acceleration (a )=  \frac{v - u}{t}  =  \frac{20 - 10}{t}  =  \frac{ 10}{t} \:  {m/s}^{2}

Distance  \: travelled = s = ut +  \frac{1}{2}  \times  {at}^{2}

135 = ut +  \frac{1}{2}  \times  {at}^{2}

135 = 10t +  \frac{1}{2}  \times ( \frac{10}{t}  \times  {t}^{2} )

t = 9s

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