Question

Please Answer the Question.

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Answer 1

$\Large{\underline{\mathfrak{Answer:}}} \\ \\ \textsf{The length of either of the remaining equal sides are } \sf \frac75 \: cm. \\ \\\Large{\underline{\mathfrak{Step-by-Step \: Explanation:}}} \\ \\ \sf Base \: of \: isosceles \: triangle = \frac43 \:cm \\ \textsf{Perimeter of triangle} \sf = \frac{62}{15} \: cm \\ \\ \textsf{Let the length of equal sides of triangle be x.} \\ \\ \sf \underline{ATQ,} \\ \sf \frac43 + x + x = \frac{62}{15} \: cm \\ \sf ⇒ 2x = (\frac{62}{15} - \frac43) \\ \sf ⇒ 2x = \frac{(62 - 20)}{15} \\ \sf ⇒ 2x = \frac{42}{15}</h2><h2> \\ \sf ⇒ x = \frac{42}{15} × \frac{1}{2} \\ \sf ⇒ x = \frac{42}{30} \\ \sf ⇒ x = \frac75 \: cm \\ \\ \textsf{The length of either of the remaining equal sides are } \sf \frac75 \: cm. \\ \\ \sf \large \underline{Thanks ..!!!}$

Answer 2

Answer:

Base = 4/3 cm

rest two eq sides = x cm

now ,

P = 62/15 cm

4/3 + 2x = 62/15

2x = 62/15 - 4/3

2x =. (62 - 20)/15

2x = 42/15

x =. 42/30

x = 7/5 Ans...