Question

please answer the question number 24 in the photo


factorization

please it is very urgent

Answer 1

hope it is right......

Answer 2

$<b >Hey here is your answer$

$= {2x}^{2} - \frac{5}{6} x + \frac{1}{12} \\ \\ = 2 {x}^{2} - \frac{2}{6}x - \frac{3}{6}x + \frac{1}{12} \\ \\ = {2x}^{2} - \frac{1}{3} x - \frac{1}{2} x + \frac{1}{12} \\ \\ = x(2x - \frac{1}{3} ) - \frac{1}{4} (2x - \frac{1}{3} ) \\ \\ = (x - \frac{1}{4} )(2x - \frac{1}{3} )$

or

$= {2x}^{2} - \frac{5}{6} x + \frac{1}{12} \\ \\ = \frac{{24x}^{2} - 10x + 1 }{12} \\ \\ = \frac{{24x}^{2}}{12} - \frac{10}{12} x + \frac{1}{12} \\ \\ \frac{{24x}^{2}}{12} - \frac{6}{12} x -\frac{4}{12} x+ \frac{1}{12} \\ \\ \frac{6}{12} x ( 4x - 1 ) - \frac{1}{12} ( 4x - 1 ) \\ \\ (\frac{6}{12} x- \frac{1}{12})( 4x - 1 )\\ \\ (\frac{1}{2} x- \frac{1}{12})( 4x - 1 )$

hope this helps you