Please answer the question only if you know it urgent....
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Simple interest on 8400 at r rate of interest and 2 years would be
8400xRx2 / 100
=168R
compound interest will be 8400(1+R/100)^2
8400(100+R/100)^2
0.84(10000+R^2)-8400
Their difference is 21 hence
168R-0.84(10000+R^2)-8400=21
solving this will give you answer
8400xRx2 / 100
=168R
compound interest will be 8400(1+R/100)^2
8400(100+R/100)^2
0.84(10000+R^2)-8400
Their difference is 21 hence
168R-0.84(10000+R^2)-8400=21
solving this will give you answer
xenon1:
you will have to factoris it and you will get two roots
a.k.a 2 answers then you will have to check which one is in the options and choose the one given or else is both are given then both options are correct
hope it helped
i know factorisation well
but
you cant r^2 - r
roots are for example( x-1) is one factor then you will equate it to zero and hence you will get x=1
you will get the same only na r^2 - r
whats the const you got in the equation
constant
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