Math, asked by Pranav777, 1 year ago

Please answer the question only if you know its very urgent...

Verify before sending answer is Rupees 6000 i.e amount of money and interest received by kamal is 600 and by anand is 615

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siddhartharao77: It should be 6000 and 6615 instead of 600 and 615.

Answers

Answered by siddhartharao77
1
Let the money lent = x.

Given rate of interest = 5%.

Given Time n = 2 years.

Now,

Given that Kamal lent the same sum of money for 2 years SI

= > x + x * 5 * 2/100

= > x + 0.1x 

= > 1.1x.



Given that Anand lent sum of money at 5% CI.

= > x [1 + 5/100]^2 [-------- A = P(1 + r/100)^n  ------ ]

= > x[21/20]^2

= > X(441/400)

= > 1.1025X.


Given that Anand received 15 more than kamal.

= > 1.1025x = 1.1x + 15

= > 0.0025x = 15

= > x = 15/0.0025

= > x = 6000.


Now,

Amount lent by Kamal = 1.1 * 6000

                                      = 6600.



Amount lent by Anand = 1.1025 * 6000

                                       = 6615.



Hope this helps!

siddhartharao77: :-)
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Answered by Anonymous
1
Hey mate!

Here's your answer!!

Kindly refer the given attachment.

Hope it helps you!!!
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