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Explanation:
1. No. of moles of ethanol= = 0.2196 ≈ 0.22
No. of moles of water = ≈ 2.78
now, formula of mole fraction=
Na= 0.22
Nb= 2.78
mole fraction of ethanol= ≈ 0.0733
molality= no of moles of solvent/mass of solvent in kilograms
now, molality = = 4.4 molal
2. molarity= no. of moles of solute / volume of solution in litres
no. of moles of Sulphuric acid = ≈ 0.056
volume of the solution = = 0.3
molarity= ≈ 0.187 M
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