Math, asked by janaki82, 1 year ago

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Answered by brainlygenius23
5

\underline{\underline{\mathfrak{\Large{Solution : }}}}\\ \\ \underline {\textsf {Given :-}} \\ \\ \sf\star\:Curved\:surface\:Area\: = 1760 cm^2 \\ \\ \sf\star\:Volume = 12320 cm^3 \\ \\ \sf\:For\:finding\:height\:of\:cylinder , \\ \\ \sf\:Curved\:Surface\:area = 1760 cm^2 \\ \\ \sf\implies\: 2\pi rh  = 1760 \\ \\ \large{\boxed{\sf { rh = 280.25 }}}\: \: \: \: ..... (1) \\ \\ \sf\:Volume = 12320 cm^3  \\ \\ \sf\implies\pi r^2 h = 12320 \\ \\ \sf\implies\: r × rh = \dfrac {12320}{3.14} \\ \\ \sf\: r = \dfrac {3923.5}{280.25} \\ \\ \large {\boxed {\sf {r = 14 cm}}} \\ \\ \sf\: Hence , \: rh = 280.25 \\ \\ \sf\:h = \dfrac {280.25}{14} \\ \\ \large {\boxed {\sf {h = 20 cm}}}

Answered by Amrit111Raj82
4

 \huge \red{Answer☝☝} \:

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