Question

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$5(2x^{2} + 3y - 8)from \: 9x ^{2} - 2y + 5$


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Answer 1

Step-by-step explanation:

5(2x^2 + 3y - 8 ) from 9x ^2 - 2y +5

= (9x^2 -2y +5) -(10x^2 + 15y -40)

= 9x^2 - 2y + 5 - 10 x^2 - 15y +40

= - x^2 - 17y +45

Answer 2

Answer:

$-x^{2} - 17y + 45$

Step-by-step explanation:

To find:

$(9x^{2} - 2y + 5) - 5(2x^{2} + 3y - 8)$

Method to find:

First, we need to simplify the second expression. We can do this by multiplying 5 with each of the terms.

$5(2x^{2} + 3y - 8)$

⇒ $10x^{2} + 15y - 40$

Now, we can subtract the expressions.

$(9x^{2} - 2y + 5) - (10x^{2} + 15y - 40)$

Since there is a negative sign outside the 2nd expression, we will have to change all of the signs in the 2nd expression in order to open the brackets. (i,e, - will become + and vice versa)

⇒ $9x^{2} - 2y + 5 - 10x^{2} - 15y + 40$

Now, we can add and subtract the like terms.

⇒ $(9x^{2} - 10x^{2} ) + (-2y -15y) + (5 + 40)$

⇒ $-x^{2} - 17y + 45$

Hope it helps!