Math, asked by Bapon14, 1 month ago

Please Answer The Question Please everyone Please It's To Argent​

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Answered by tarracharan
0

(i) \sf{ {2}^{ \frac{5}{6} }  \times  {2}^{  \frac{1}{6}  }  =  {2}^{ (\frac{5}{6}  +  \frac{1}{6}) }  =  {2}^{ \frac{6}{6} } = }{\large{\red{\sf{2}}}}

(ii)\sf{ \sqrt[5]{32}  \times  \sqrt[5]{243}  =  \sqrt[5]{ {2}^{5} }  \times  \sqrt[5]{ {3}^{5} }  = 2 \times 3 = }{\large{\red{\sf{6}}}}

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