Question

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Answer 1

Answer:

Given: area of square =5184m

2

∴ Side of square =

5184

=72m

The perimeter of square =4×72=288m

Let breadth of rectangle =xm

∴ Length of rectangle =2xm

Now, perimeter of rectangle= Perimeter of a square

⇒2(l+b)=288m

⇒2(2x+x)=288

⇒x=

6

288

=48m

∴ Length =2×48=96m, Breadth =48m

Therefore area of rectangle =l×b=96×48=4608m

2

Step-by-step explanation:

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Answer 2

$\sf\bold{\underline{Given:}}$

• Area of square = $\sf{5184{m}^{2}}$
• Perimeter of square is same as perimeter of square.
• Length of rectangle is twice it's breadth.

$\sf\bold{\underline{Formula\:used:}}$

• Side of square = $\sf{ \sqrt{area\:of\:square}}$
• Perimeter of square = $\sf{4 \times side}$
• Perimeter of rectangle = $\sf{2(Length + Breadth)}$
• Area of rectangle = $\sf{Length \times Breadth}$

$\sf\bold{\underline{Solution:}}$

Let,

$\longmapsto$Breadth of rectangle (B)= x m

$\longmapsto$Length of rectangle (L) = 2x m

First, let us find perimeter of square using its area.

$\sf\longmapsto{Area\:of\:square\:=\:5184 {m}^{2}}$

$\sf\longmapsto{Side\:of\:square\:=\: \sqrt{5184}=72m}$

$\sf\longmapsto{Perimeter\:of\:square\:=\: 4 \times 72 \:=\:288m}$

According to the condition given in question that perimeter of square is equal to perimeter of rectangle.

$\sf\longmapsto{\therefore\:Perimeter\:of\:rectangle\:=\:Perimeter\:of\:square}$

$\sf\longmapsto{2(L + B) = 288m}$

$\sf\longmapsto{2(2x + x) = 288m}$

$\sf\longmapsto{6x = 288m}$

$\sf\longmapsto{x =\dfrac{288m}{6}=48m}$

$\sf\longmapsto{Breadth\:of\:rectangle\:=\:x\:=48m}$

$\sf\longmapsto{Length\:of\:rectangle\:=\:2x\:=2 \times 48m\:=\:96m}$

$\sf\longmapsto{\therefore{Area\:of\:rectangle\:=\:L \times B \:=\: 96 \times 48 \:=\:4608 {m}^{2}}}$

$\sf\bold{\underline{Answer:}}$

$\sf\mapsto{Area\:of\:rectangle\:is\:4608 {m}^{2}}$

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