please answer the question quickly
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Hey!!
Here is your answer,,
As it is given that pole was broken from ground of 9 m height.
It touches the ground at 16m.
Height of pole = AB = 9cm
Touches the ground = BC = 16m
AB + AC = Length of the pole
so, we get ∆ABC as a right angled triangle.
AC^2 = AB^2 + BC^2
= (9)^2 + (16)^2
= 81 + 256
AC = √337
AC = 18.35m
Length of the pole = AB + AC
= 9 + 18.35
= 27.35
Hope it helps you ...
Thanks...
Here is your answer,,
As it is given that pole was broken from ground of 9 m height.
It touches the ground at 16m.
Height of pole = AB = 9cm
Touches the ground = BC = 16m
AB + AC = Length of the pole
so, we get ∆ABC as a right angled triangle.
AC^2 = AB^2 + BC^2
= (9)^2 + (16)^2
= 81 + 256
AC = √337
AC = 18.35m
Length of the pole = AB + AC
= 9 + 18.35
= 27.35
Hope it helps you ...
Thanks...
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ria113:
thanks fot brainliest
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