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His starting salary = Rs.1300 and fixed Increment = Rs.50
Step-by-step explanation:
Let his salary be x and his fixed increment be y.
After 4 years of service → x + 4y = 1500 → (1)
After 10 years of service → x + 10y = 1800 → (2)
Subtracting, - 6y = - 300
Thus, y = =50
Putting y = 50 in x + 4y = 1500
We get, x = = 1500 - 200 = 1300
Hence, his starting salary = Rs.1300
Fixed Increment = Rs.50
________[_________[[_[[_[[[[[[[[[_____
Mar ME UHHHH BRAINLIEST
Step-by-step explanation:
Let his salary be x and his fixed increment be y.
After 4 years of service → x + 4y = 1500 → (1)
After 10 years of service → x + 10y = 1800 → (2)
Subtracting, - 6y = - 300
Thus, y = =50
Putting y = 50 in x + 4y = 1500
We get, x = = 1500 - 200 = 1300
Hence, his starting salary = Rs.1300
Fixed Increment = Rs.50
________[_________[[_[[_[[[[[[[[[_____
Mar ME UHHHH BRAINLIEST
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