Math, asked by Khushmeetkaurhangla, 1 year ago

please answer the question . The first answerer will be marked brainiest . ques 5 (part 1,3,6)

Attachments:

Answers

Answered by siddhartharao77
1
(1)

= > (4x^2 - 4x + 1) * (2x^2 + x - 2)

= > 4x^2 * 2x^2 + 2x^2 * x - 4x^2 * 2 - 4x * 2x^2 - 4x * x - 2 + 2x^2 + x - 2

= > 8x^4 + 4x^3 - 8x^3 - 8x^2 - 4x^2 + 2x^2 + 9x - 2

= > 8x^4 - 4x^3 - 10x^2 + 9x - 2.


(3)

(4x^2 + 24xy + 3y^2) * (x^2 - xy + y^2)

= > 4x^2 * x^2 - 4x^2 * xy + 4x^2 * y^2 + 24xy * x^2 - 24xy * xy + 24xy * y^2 + 3y^2 * x^2 - 3y^2 * xy + 3y^2 * y^2

= > 4x^2x^2 + 20x^2xy + 7x^2y^2 - 24x^2y^2 + 24xy^2y - 3xy^2y + 3y^2y^2

= > 4x^4 + 20x^3y - 17x^2y^2 + 21xy^3 + 3y^4.



(6)

(3x^5  - 7x^3 + 2x^2  - x + 4) * (x^3 - 2x^2 + 3x - 1)

= > 3x^5 * x^3 - 3x^5 * 2x^2 + 3x^5 * 3x - 3x^5 * 1 - 7x^3 * x^3 + 7x^2 * 2x^2 - 7x^3 * 3x + 7x^3 + 2x^2 * x^3 - 2x^2 * x^2 + 2x^2 * 3x - 2x^2 -  x^4 + 2x^3 - 3x^2 + x + 4x^3 - 8x^2 + 12x - 4

= > 3x^8 - 6x^7 + 9x^6 - 7x^6 + 3x^5 + 14x^5 + 2x^5 - 21x^4 - 4x^4  - x^4  + 19x^3 - 13x^2 + 13x - 4

= > 3x^8 - 6x^7 + 2x^6 + 13x^5 - 26x^4 + 19x^3 - 13x^2 + 13x - 4.




Hope this helps!

siddhartharao77: :-)
Khushmeetkaurhangla: :-)
Similar questions