Please answer the question urgently
Attachments:
Answers
Answered by
7
27^log2=8^log3 take log of both sides: log(27log2)=log(8log3)
bring down the exponent so (log2)log27=(log3)log8
then log27/log3=log8/log2
use identity logax/logab=logbx
so that log327=log28 --> 3=3 (which is true)
If you like my answer mark as BRAINLIST and follow me.
bring down the exponent so (log2)log27=(log3)log8
then log27/log3=log8/log2
use identity logax/logab=logbx
so that log327=log28 --> 3=3 (which is true)
If you like my answer mark as BRAINLIST and follow me.
harshbhardwaj23:
mark as BRAINLIST
Answered by
0
Answer:
Step-by-step explanation:
LHS
27log2
=3^3log2
=log(2^3)^3
=log8^3
=log512
RHS
8log3
=2^3log3
=log(3^2)^3
=log9^3
=log512
Therefore, LHS=RHS
PROVED!!!!
Similar questions