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Answer: 1. limiting reagent= Chlorine
2. amount of HCl formed=
71 g Cl2 gives → 73 g HCl
1 g Cl2 → 73/71 g HCl
135 g Cl2 → 73/71× 135 = 138.80 i.e. 139 g HCl
3. amount of unused reactant =
71 g Cl2 reacts with → 2g H2
1 g Cl2 → 2/71 g H2
135 gCl2→ 2/71 × 135 = 3.8 i.e. 4 g H2
4. amount of reactant to be added=
2 g H2 reacts with = 71 g Cl2
1 g H2 reacts with = 71/2 g Cl2
6 g H2 reacts with = 71/2 * 6 = 213 g Cl2
therefore cl2 to be added to complete reaction is 213 - 135 = 78 g Cl2
Explanation:
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