Physics, asked by arnav52, 1 year ago

please answer the question with full steps

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Answered by har3nd3rpapssj

The displacement is equal to the area under the velocity-time curve. As velocity is increasing and is in only one direction, the distance and displacement are same. The slope of the curve is "m". Therefore, m= tanΘ = u/T,
T= $\frac{u}{m}$ .....(1)
Now displacement or distance= Area of velocity-time curve = Area of Triangle= $\frac{1}{2}\times u\times T$ ......(2)
From (1) and (2), we get,
Distance= $\frac{ u^{2} }{2m}$

har3nd3rpapssj: No problem. Slope of the graph= u/T

arnav52: thnx

arnav52: can yoi solve my previous questions

har3nd3rpapssj: In a right-angled triangle, tan(angle)=opposite side to that angle/adjacent side to that angle. In your question, there is a right angled triangle, let's consider the angle made by velocity line with x-axis. In this case, side opposite to that angle is u and side adjacent to that angle is T, hence tan(angle)=u/T

har3nd3rpapssj: Where can I find those question?

arnav52: i am saying can you answer my previous questions which no one was able to solve

arnav52: in my id

har3nd3rpapssj: Okay, I'll try.

arnav52: just click on my id then click on my qustion then select physics or cbsce board 12th there youll find questions with no answers

arnav52: hey please do more of my questions you are genius

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