Math, asked by dimprajapati, 2 months ago

please answer the question with Solution ​

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Answers

Answered by zobiyasayyed
3

Step-by-step explanation:

à)1

1 is the correct answer ..

Answered by snehitha2
3

Question :

Choose the correct alternatives for :-

tanθcotθ = ____

a) 1

b) 0

c) 1/2

d) √3/2

Answer :

option a) 1

Step-by-step explanation :

  • cotθ = 1/tanθ

So,

tanθcotθ

= tanθ × 1/tanθ

= 1

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Know more :

Trigonometric values :

\Large{ \begin{tabular}{|c|c|c|c|c|c|} \cline{1-6} \theta & \sf 0^{\circ} & \sf 30^{\circ} & \sf 45^{\circ} & \sf 60^{\circ} & \sf 90^{\circ} \\ \cline{1-6} $ \sin $ & 0 & $\dfrac{1}{2 }$ & $\dfrac{1}{ \sqrt{2} }$ & $\dfrac{ \sqrt{3}}{2}$ & 1 \\ \cline{1-6} $ \cos $ & 1 & $ \dfrac{ \sqrt{ 3 }}{2} } $ & $ \dfrac{1}{ \sqrt{2} } $ & $ \dfrac{ 1 }{ 2 } $ & 0 \\ \cline{1-6} $ \tan $ & 0 & $ \dfrac{1}{ \sqrt{3} } $ & 1 & $ \sqrt{3} $ & $ \infty $ \\ \cline{1-6} \cot & $ \infty $ &$ \sqrt{3} $ & 1 & $ \dfrac{1}{ \sqrt{3} } $ &0 \\ \cline{1 - 6} \sec & 1 & $ \dfrac{2}{ \sqrt{3}} $ & $ \sqrt{2} $ & 2 & $ \infty $ \\ \cline{1-6} \csc & $ \infty $ & 2 & $ \sqrt{2 } $ & $ \dfrac{ 2 }{ \sqrt{ 3 } } $ & 1 \\ \cline{1 - 6}\end{tabular}}

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Identities :

sin²θ + cos²θ = 1

cosec²θ - cot²θ = 1

sec²θ - tan²θ = 1

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Trigonometric functions and their relation with the sides of right angled triangle :

sinθ = opposite side/hypotenuse

cosθ = adjacent side/hypotenuse

tanθ = opposite side/adjacent side

cosecθ = 1/sinθ = hypotenuse/opposite side

secθ = 1/cosθ = hypotenuse/adjacent side

cotθ = 1/tanθ = adjacent side/opposite side

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