please answer the question with solution...
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HEY MATE , HERE IS UR ANSWER.✌✌❤❤
Option ( A ) ZERO is the correct answer.
BRIEFLY SOLVED.....
A+B+C=180
B+C=180-A
sin(B+C)=sin(180-A)
sin(B+C)=sin A …(Because sin(180-y)=sin y)
Also cos B×cos C=cos A
tan A -tan B -tan C
=tan A -(sin B/cos B + sin C/cos C)
=tanA -(sinB×cosC + sinC×cos B)/(cosB×cosC)
=tanA -(sin(B+C))/(cosB×cosC)
=tan A -sin A/cos A
=tan A -tan A
=0
HOPE IT HELPS YOU.✌
#BE BRAINLY.❤❤
Option ( A ) ZERO is the correct answer.
BRIEFLY SOLVED.....
A+B+C=180
B+C=180-A
sin(B+C)=sin(180-A)
sin(B+C)=sin A …(Because sin(180-y)=sin y)
Also cos B×cos C=cos A
tan A -tan B -tan C
=tan A -(sin B/cos B + sin C/cos C)
=tanA -(sinB×cosC + sinC×cos B)/(cosB×cosC)
=tanA -(sin(B+C))/(cosB×cosC)
=tan A -sin A/cos A
=tan A -tan A
=0
HOPE IT HELPS YOU.✌
#BE BRAINLY.❤❤
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B+C=180-A
sin(B+C)=sin(180-A)
sin(B+C)=sin A …(Because sin(180-y)=sin y)
Also cos B×cos C=cos A
tan A -tan B -tan C
=tan A -(sin B/cos B + sin C/cos C)
=tanA -(sinB×cosC + sinC×cos B)/(cosB×cosC)
=tanA -(sin(B+C))/(cosB×cosC)
=tan A -sin A/cos A
=tan A -tan A
=0