please answer the questions
1/7(3x-5)^2=28
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1/7 *(3x-5)^2 =28
(3x-5)^2 = 28*7
(3x-5)^2 = 196
3x-5 = 14
3x= 14+5
x= 19/3
i hope this will help
- by ABHAY
(3x-5)^2 = 28*7
(3x-5)^2 = 196
3x-5 = 14
3x= 14+5
x= 19/3
i hope this will help
- by ABHAY
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Answered by
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