Question

please answer the questions

Answer 1

In triangles,PAB and PDC
AB=CD [Given]
angle APB=angle DPC [Vertically Opposite Angles]
PB=PD [Radii of the circle]
Therefore,triangle PAB is congruent to triangle PDC. [SAS congruency rule]


PA=PD [Radii of the circle]
PC=PB [Radii of the circle]

As AB and CD are equal,they are parallel to each other.
Then the other two sides are also parallel to each other.
Therefore,AD//BC

hence proved.

hope this helps

please mark as brainliest answer.☺