Question

Please answer the questions​

Answer 1

for the 1st one

no. of cubical boxes can be stored in godown = n

n = (volume of godown)/volume of each box)

hence,

n = (60 x 40 x 30 )/0.8

n= 90,000

hence 90,000 boxes can be kept in the godown

for 2nd one

since the sheet is folded in form of cylinder the curved surface area of the cylinder is equal to 11

2(22/7)r(4) = 11

since height is 4 and pi value is 22/7

radius (r) is 7 from the above equation

volume of the cylinder is pi x rsquare x h

hence v = 22/7 x 7square x 4

v = 616 cm cube