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Given that
(x+1)and(x+2) are two factors of cubic polynomial: x³+3x²-2px+q
Since it is a cubic Polynomial; let us assume its third factor be (x+k)
Hence we should have
(x+1)(x+2)(x+k)= x³+3x²-2px+q
On multiplying the factors on LHS and arranging the term of like power; we get
x³+x²(k+3)+x(3k+2)+2k= x³+3x²-2px+q
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