please answer the questions
Answers
Answer:
See
Step-by-step explanation:
Third side of the triangle is \mathbf{2x^{3}-5x^{2}}2x
3
−5x
2
Step-by-step explanation:
1. In question you have write find out third side of rectangle but it should be third side of triangle.
2. Let triangle is ABC. Let
\mathbf{Perimeter \ (P)= 5x^{2}+3x-1}Perimeter (P)=5x
2
+3x−1
\mathbf{AB=2x-5+7x^{2}}AB=2x−5+7x
2
CA = unknown
\mathbf{BC=3x^{2}+4-2x^{3}+x}BC=3x
2
+4−2x
3
+x
3. We know that perimeter of triangle is
P = AB + BC + CA
Putting respective value in above equation
\mathbf{5x^{2}+3x-1=+2x-5+7x^{2}+3x^{2}+4-2x^{3}+x+CA}5x
2
+3x−1=+2x−5+7x
2
+3x
2
+4−2x
3
+x+CA
⇒\mathbf{5x^{2}+3x-1=-2x^{3}+10x^{2}+3x-1+CA}5x
2
+3x−1=−2x
3
+10x
2
+3x−1+CA
So
\mathbf{CA=5x^{2}+3x-1+2x^{3}-10x^{2}-3x+1}CA=5x
2
+3x−1+2x
3
−10x
2
−3x+1
\mathbf{CA=2x^{3}-5x^{2}}CA=2x
3
−5x
2
= This is third side of triangle.