Math, asked by sreekarreddy91, 1 month ago

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Answered by tennetiraj86
5

Answer:

13. a

14. a

15. a

16. a

Step-by-step explanation:

13)

Given that : (3/7)÷ (7/-4)

=> (3/7)×(-4/7)

=> (3×-4)/(7×7)

=> -12/49

The value of (3/7)÷ (7/-4) is -12/49

14)

Given number = 5/7

Additive inverse of 5/7 is -5/7

15)

Let the rational number be a/b

The inverse of a/b = b/a

Their product = (a/b)×(b/a) = (ab)/(ab) = 1

The product of a rational number and it's inverse is 1.

16)

One of the numbers = -10

Let the other number be X

Their product = -10×X = -10X

According to the given problem

The product of two numbers = 15

=> -10X = 15

=> X = -15/10

=> X = -3/2

The other number = -3/2

17)

a) Distributive Property under multiplication over addition

b) (-11/5×5/6)×3 = (3×5/6)×-11/5

Associative Property

c) Multiplicative Inverse

d)Multiplicative Identity

e) Commutative Property

18)

See the above attachment

19) -3/5 , 25/-29, -15/7 are the left side to the zero.

7/9 , -11/-13, 1/10 are the right side to the zero.

20)

Given numbers are -1 and 1

The Mean method : The ration number between a and b is (a+b)/2

i) (-1+1)/2 = 0/2 = 0

ii) Rational number between -1 and 0 = (-1+0)/2 = -1/2

iii) The rational number between 0 and -1/2

=>[0+(-1/2)]/2

=>(2-1)/2/2

=> 1/4

iv) The rational number between 1/4 and 0

=> [(1/4)+0]/2

=> (1/4)/2

=>1/8

v) The rational number between 0 and 1/8

=> (0+1/8)/2

=> (1/8)/2

=> 1/16

The rational numbers are -1/2,0,1/4,1/8,1/16

21)

Given numbers are 2 and 3

Required rational numbers = 5

On writing the denominator as (5+1) = 6

=> 2×(6/6)=(2×6)/6 = 12/6

=> 3×(6/6)=(3×6)/6 = 18/6

The rational numbers = 13/6 , 14/6, 15/6, 16/6 ,17/6

22)

a) Given numbers are 1/2 and 2/3

required numbers = 10

On writing the denominator as (10+1) = 11 multiple

=> 1/2 = (1/2)×(33/33) = 33/66

=> 2/3 = (2/3)×(22/22) = 44/66

The required numbers are 34/66,35/66,36/66,37/66, 38/66,39/66, 40/66, 41/66,42/66,43/66

b) Given numbers are -3/4 and -4/5

required numbers = 10

On writing the denominator as (10+1) = 11 multiple

=> -3/4 = (-3/4)×(55/55 )= -165/220

=> -4/5 = (-4/5)×(44/44) = -176/220

The required numbers are -166/220, -167/220, -168/220, -169/220, -170/220, -171/220, -172/220,-173/220, -174/220 , -175/220

c)Given numbers are 2/7 and 2

required numbers = 10

=> 2= (2)×(7/7) =14/7

The required numbers are 3/7,4/7,5/7,6/7,7/7,8/7,9/7,10/7,11/7,12/7,13/7

d)Given numbers are -3 and -7/5

required numbers = 10

=> -3 = (-3)×(10/10) = -30/10

=> -7/5 = (-7/5)×(2/2) = -14/10

The required numbers are -15/10,-16/10,

-17/10, -18/10,-19/10,-20/10,-21/10,-22/10,

-23/10,-24/10 -25/10,-26/10,-27/10,-28/10,

-29/10

23)

a) |-7/24 | = 7/24

8/24 , 10/24 15/24 , 25/24, 47/24

b) | 7/13 + (-2/13) |

=> | (7-2)/13 |

=> | -2/13 |

=> 2/13

5/13 , 14/13 ,15/13 , 22/13, 25/13

c) | -16/35 | + |-11/21 |

=> 16/35 + 11/21

LCM of 35 and 21 = 105

=> (48+55)/105

=> 103/105

104/105 , 106/105, 200/105, 205/105, 209/105

d) | -14/27 | +|-3/20|

=> (14/27)+(3/20)

LCM of 27 and 20 = 540

=> (280+81)/540

=> 361/540

390/540, 550/540, 650/540, 1000/540, 1079/540

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