Question

please answer the questions​

Answer 1

Answer:

c is the best answer for the

Answer 2

Question:

A carbon resistor of (47 ± 4.7)kΩ is to be marked with rings of different colours for its identification. The colour códe sequence will be:

(1) Violet - Yellow - Orange - Silver

(2) Yellow - Violet - Orange - Silver

(3) Green - Orange - Violet - Gold

(4) Yellow - Green - Violet - Gold

Answer:

Option (2)

Explanation:

Resistor color códes :

⇒ The first two bands indicate the value of the resistance.

⇒ The third band, simply indicates the number of zeros. (multiplier)

⇒ The fourth band indicates the tolerance.

$\boxed{\begin{array}{|c|c|c|c|}\cline{1-4}\sf Colour &\sf Number&\sf Multiplier&\sf Tolerance\\\cline{1-4}\sf Black&\sf 0&\sf 1&\\\cline{1-4}\sf Brown&\sf 1&\sf 10^1 &\sf \\\cline{1-4}\sf Red&\sf 2&\sf 10^2&\\\cline{1-4}\sf Orange&\sf 3&\sf 10^3& \\\cline{1-4}\sf Yellow&\sf 4&\sf 10^4&\\\cline{1-4}\sf Green&\sf 5&\sf 10^5 &\sf \\\cline{1-4}\sf Blue&\sf 6&\sf 10^6& \\\cline{1-4}\sf Violet&\sf 7&\sf 10^7&\\\cline{1-4}\sf Gray&\sf 8&\sf 10^8&\\\cline{1-4}\sf White&\sf 9&\sf 10^9 &\sf \\\cline{1-4}\sf Gold& &\sf 10^{-1}& \sf 5\% \\\cline{1-4}\sf Silver& & \sf 10^{-2}& \sf 10\% \\\cline{1-4}\sf No \: colour & & & \sf 20\% \\\cline{1-4}\end{array}}$

Given resistance of carbon resistor is (47 ± 4.7) kΩ

• first digit = 4 ⇒ Yellow

• second digit = 7 ⇒ Violet

• multiplier = 10³ (observe the units - kΩ) ⇒ Orange

• tolerance = 4.7/47 × 100

                   = 10% ⇒ Silver

Hence, the colour códe sequence is Yellow - Violet - Orange - Silver