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Given , - 11x + [ 2x/3 + 3 ] = 5 - 2[ x/3 + 1]
---------------------------------------------------------
Proof :-
LHS --------------------------------------------------
==> - 11x + [ 2x + 9/3]
==> - 11x + 2x + 9/3
==> -33x + 2x + 9/3
==> -31x +9/3..............(1)
-------------------------------------------------------
RHS -------------------------------------------------
==> 5 - 2[ x + 3/3]
==> 5 - 2x - 6/3
==> 15 -2x - 6/3
==> 9 - 6x /3.........(2)
Equating (1) and (2)
==> -21x + 9/3 = 9 - 6x/3
==> -21x + 9 = 9 - 6x
==> -21 x + 6x = 9 - 9
==> -15x = 0
==> x = 0
Therefore, the value of x is 0
---------------------------------------------------------
Proof :-
LHS --------------------------------------------------
==> - 11x + [ 2x + 9/3]
==> - 11x + 2x + 9/3
==> -33x + 2x + 9/3
==> -31x +9/3..............(1)
-------------------------------------------------------
RHS -------------------------------------------------
==> 5 - 2[ x + 3/3]
==> 5 - 2x - 6/3
==> 15 -2x - 6/3
==> 9 - 6x /3.........(2)
Equating (1) and (2)
==> -21x + 9/3 = 9 - 6x/3
==> -21x + 9 = 9 - 6x
==> -21 x + 6x = 9 - 9
==> -15x = 0
==> x = 0
Therefore, the value of x is 0
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