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Answered by HEMANTHKUMAR007
0
Given , - 11x + [ 2x/3 + 3 ] = 5 - 2[ x/3 + 1]

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Proof :-

LHS --------------------------------------------------

==> - 11x + [ 2x + 9/3]

==> - 11x + 2x + 9/3

==> -33x + 2x + 9/3

==> -31x +9/3..............(1)

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RHS -------------------------------------------------

==> 5 - 2[ x + 3/3]

==> 5 - 2x - 6/3

==> 15 -2x - 6/3

==> 9 - 6x /3.........(2)

Equating (1) and (2)

==> -21x + 9/3 = 9 - 6x/3

==> -21x + 9 = 9 - 6x

==> -21 x + 6x = 9 - 9

==> -15x = 0

==> x = 0

Therefore, the value of x is 0

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