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Answers
Answer:
answer no .3 a dice is thrown 1 time so the chances of getting
3.1. an even number is 3/6= 1/2
3.2a number greater than 3is 3/6= 1/2
3.3.a number between 3 and 6 is =2/6 =1/3
answer no 4. one card is drawn from a well shuffled deck of 52 cards probability of drawing
4.1 an ace = 4/52 =1/13
4.2 '2'of spades = 1/17
4.3 10 of black suit = 2 /52=1/26
Step-by-step explanation:
3.1
One rolling a die we can get a 1 or 2, or a 3, or a 4, or a 5 or a 6.
Out of these 2, 4 and 6 are even numbers.
Probability of get an even number on rolling a die = 3/6 = 1/2 or 50%
3.2
If you roll a single die there are 6 possible outcomes (1,2,3,4,5,6), 3 of which are greater than 3. So in a single roll the probability of getting a number greater than 3 is 3/6 = 1/2
3.3.
rolling a dice once we have following outcomes
1,2,3,4,5,6
Now for the Event when we get a number between 3 and 6
We have
4 and 5
Then the probability of this event is given by
P(getting no. 3 and 6)= 2/6= 1/3
4.1
there are 52 card from which the probability of drawing an ace is to be calculated by 4/52 because a deck of 52 cards contains only 4 aces so 4/52 =1/13
4.2
The product of two probabilities is the total probability to draw two cards of the same given unit, that is 1/(13×17)=1/221. Since there are 13 units, this needs to be multiplied by the number of units, that is 13. Thus the answer is 1/221×13/1=1/17
4.3
Since, there are two cards of ' 10' of a black suit, one JO of spade and other 10 of club, so the probability of drawing 10 of a black suit =2/52=1/26.
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