Question

please answer the questions as soon as possible.

Answer 1

This is the answer I hope this may help you...

Answer 2

Hey Mate,

Given,

=> $\frac{2^{n-1}+2^n}{2^{n+1}-2^n }=\frac{3}{2}$

Now,

=> $\frac{2^{n-1}(1+2)}{2^{n-1}(4-2)}=\frac{3}{2}$

Now, on cancelling the common number in both numerator and denominator, we get :-

=> $\frac{1+2}{4-2}$ = $\frac{3}{2}$

=> $\frac{3}{2} = \frac{3}{2}$

Since, LHS and RHS are equal, it is proved that :-

$\frac{2^{n-1}+2^n}{2^{n+1}-2^n }=\frac{3}{2}$

Hope it Helps!