Question

please answer the questions (beaware that some/all ticked answers are wrong) please give descriptive answer

Answer 1

4)d
5)c
1 mole of any element=6.023×10²³ atoms
So,1 mole atoms of He=6.023×10²³ atoms of He=4g of He
remaining option is c.so,it is answer.
6)a
No.of atoms in any element of 1g is 6.023×10²³
So,no.of carbon atoms of 1g of CaCO3 is 6.023×10²³
7)c
For,
6.023×10²³......…...........................108 u
6.023×10^20.................................?
= 6.023×10^20 ×108÷6.023×10²³
= 108×10^20/10²³
= 108×10^-3
=108/1000
=0.108 g

please mark as brainliest answer

Answer 2

4) d : N2,O2,Cl2
5) c : 1 atom of He
6) a : 6.023 ×10^23 atoms
7) c : 0.108 g


Hope it helps...............