Question

Please answer the questions correctly​

Answer 1

Step-by-step explanation:

$(\frac{2}{3})^{3}\times (\frac{2}{3})^{-2} \times [(\frac{1}{2})^{2}]^{-2}\times(\frac{1}{24})\\\\= (\frac{2}{3})^{3}\times (\frac{2}{3})^{-2} \times [(\frac{1}{2})^{-4}]\times(\frac{1}{24})\,\,[(a^{m})^{n}= a^{mn}]\\\\= (\frac{2}{3})^{[3+(-2)]} \times [(\frac{1}{2})^{-4}]^\times(\frac{1}{24})\,\,[a^{m}\times a^{n}= a^{m+n}]\\\\= (\frac{2}{3}) \times [(\frac{1}{2})^{-4}]\times(\frac{1}{24})\\\\= (\frac{2}{3}) \times [(\frac{1}{2})^{-4}]\times(\frac{1}{8})(\frac{1}{3})$

$\\= (\frac{2}{3}) \times [(\frac{1}{2})^{-4}]\times(\frac{1}{2})^{3}(\frac{1}{3})\\\\= (\frac{2}{3}) \times [(\frac{1}{2})^{-4+3}]\times (\frac{1}{3})\,\, [a^{m}\times a^{n}= a^{m+n}]\\\\= (\frac{2}{3}) \times [(\frac{1}{2})^{-1}]\times (\frac{1}{3})\\\\= (\frac{2}{3}) \times (\frac{2}{1})\times (\frac{1}{3})\,\,[a^{-1}= \frac{1}{a}]$

$\\= \boxed {\bf \frac {4}{9}}$

Hope this helps! Please mark as brainliest!

Answer 2

Step-by-step explanation:

In law, an answer was originally a solemn assertion in opposition to someone or something, and thus generally any counter-statement or defense, a reply to a question or response, or objection, or a correct solution of a problem.