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In the rectangle PQRS ,
PQ = 6 cm
PR = 10 cm
QR² = PR²-PQ² [By Pythagoras theorem]
QR² = 10²-6²
QR² = 100-36
QR² = 64
Taking square roots both side :
√QR² = √64
QR = 8 cm
Now ,
Perimeter of the rectangle PQRS =
2(Length+Breadth)
= 2(8+6)
= 2×14 cm = 28cm
PQ = 6 cm
PR = 10 cm
QR² = PR²-PQ² [By Pythagoras theorem]
QR² = 10²-6²
QR² = 100-36
QR² = 64
Taking square roots both side :
√QR² = √64
QR = 8 cm
Now ,
Perimeter of the rectangle PQRS =
2(Length+Breadth)
= 2(8+6)
= 2×14 cm = 28cm
Answered by
1
2(10+6)
Hope it helps you
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