please answer the questions fast.
I will mark you as brainlist.
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what chapter and class are u in
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i will tell then
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∴ OP bisects ∠BOC
∴ ∠POC = 1/2 ∠BOC ...(i)
Also OQ bisects ∠AOC
∴ ∠COQ = 1/2 ∠AOC ...(ii)
∴ OC stands on AB
∴ ∠AOC + ∠BOC = 1800 [Linear pair]
⇒ 1/2 ∠AOC + 1/2 ∠BOC = 1/2 × 1800
⇒ ∠COQ + ∠POC = 900 [Using (i) & (ii)] ⇒ ∠POQ = 900 [By angle sum property]
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