Question

Please answer the questions in the attachment

Answer 1

40-25=15
A traider Gain 15%of cost price

Answer 2

Answer:

3. 105%

4. Area of the park = (11x² - 7x + 55xy - 35y) m²

Area after verification is 11330 m²

Step-by-step explanation:

3. Let the cost price be x.

∴ Marked price = x + 40% of x = x + 40x/100 = x + 2x/5 = 7x/5

Discount % = 25 %

∴ Discount price = 25 % of 7x/5

= 25/100 × 7x/5

= 7x/20

So, price after discount, i.e., Selling price = 7x/5 - 7x/20 = 21x/20

∴ Gain percent = (21x/20)/x × 100 = 21/20 × 100 = 105% (answer)

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4. let the length l = (11x - 7) m

and breadth b = (x + 5y) m

∴ Area of the park = l×b

= (11x - 7)(x + 5y) = (11x² - 7x + 55xy - 35y) m² (answer)

Verification of this question:

Putting x=10 and y=20,

Area = 11(10)² - 7(10) + 55(10)(20) - 35(20)

= 1100 - 70 + 11000 - 700

= 11330 m² (verified)