Question

please answer the questions please​

Answer 1

Answer:

1. (4,3)

2. 2

Step-by-step explanation:

1. Any one solution of the equation can be : (4,3) where x=4 and y=3.

(On putting the values, we get 4 + 3 = 7).

2. Given equations are:

3x + 5y = 9               ...(i)

5x + 3y = 7               ...(ii)

On adding (i) and (ii), we get:

  3x + 5y = 9

+

  5x + 3y = 7

---------------------

  8x + 8y = 16

⇒8(x+y) = 16

⇒(x+y) = 16/8

⇒(x+y) = 2

Answer 2

Answer:

$\frac{3x}{5x} \: + \frac{5x}{3y} = \frac{9}{7} \frac{eq...1}{eq...2} \frac{ \times }{ \times } \frac{5}{3} \\ now \\ \frac{15x}{15x} + \frac{25y}{9y} = \frac{45}{21} \\ using \: elimintion \: method \\ 16y = 24 \\ y = \frac{24}{16 } = \frac{3}{2 } \\ putting \: y \: in \: equation \: 1 \\ 3x + 5 \times \frac{3}{2} = 9 \\ x + \frac{15}{2} = 3 \\ x = 3 - \frac{15}{2} \\ x = \frac{6 - 15}{2} = \frac{9}{2} \\ ans.$