Math, asked by Anonymous, 10 months ago

please answer the questions please and explain it also! if you want brainlist so answer questions please!

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Answers

Answered by tahseen619
6

Answer:

1.

i. Rs 307.5

ii. Rs 630.5

iv. Rs 208

Step-by-step explanation:

{\underline{{\text{Using Formula}}}}

{{\boxed{ C.I =  P   \{ (1+ \frac{r}{100})^ {t} -1 \} }}}

Where,

C.I = Compound Interest

P = Principal

t = time

r = rate of interest

{\underline{{\text{Solution:}}}}

i. Amount

3000(1 +  \frac{5}{100}) {}^{2}  \\  \\ =  3000( \frac{105}{100} ) {}^{2}  \\  \\  = 3000 {( \frac{21}{20} )}^{2}  \\  \\ =  3000  \times \frac{21}{20}  \times  \frac{21}{20}  \\  \\ =   \cancel{3000}  \times \frac{21}{ \cancel{20}}  \times  \frac{21}{ \cancel{20}}  \\  \\ =  15 \times  \frac{441}{2}  \\  \\   = \frac{6615}{2}  \\  \\  = 3307.5

C.I = Rs ( 3305.8 - 3000) = Rs 307.5

ii. Amount

4000(1 +  \frac{5}{100}) {}^{3}  \\  \\ =  4000( \frac{105}{100} ) {}^{3}  \\  \\  = 4000 {( \frac{21}{20} )}^{3}  \\  \\ =  4000\times \frac{21}{20}  \times  \frac{21}{20} \times  \frac{21}{20}   \\  \\ =   \cancel{4000}  \times \frac{21}{ \cancel{20}}  \times  \frac{21}{ \cancel{20}}  \times  \frac{21}{ \cancel{20}}\\  \\ =   \frac{9261}{2}  \\  \\   = 4630.5

C.I = Rs (4630.5 - 4000) = Rs 630.5

iv.

1250(1 +  \frac{8}{100}) {}^{2}  \\  \\ =  1250( \frac{108}{100} ) {}^{2}  \\  \\  = 1250 {( \frac{27}{25} )}^{2}  \\  \\ =  1250\times \frac{27}{25}  \times  \frac{27}{25}   \\  \\ =   \cancel{1250}  \times \frac{27}{ \cancel{25}}  \times  \frac{27}{ \cancel{25}}  \\  \\ =   2 \times 729 \\  \\   = 1458

C.I = Rs (1458 - 1250) = Rs 208

Answered by Anonymous
0

Answer:

1) 306.5

2)632

3)207.5

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