please answer the questions which is in the image
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[tex]\mathfrak{\huge{Answer:-}} \\ \frac{4x + 3y}{4x - 3y} = \frac{43}{13} \\ Cross \: multiply \\ 13(4x + 3y) = 43(4x - 3y) \\ 52x + 39y = 172x - 129y \\ 52x - 172x = ( - 129y) - 39y \\ ( - 120x) = ( - 168y) \\ 120x = 168y \\ \boxed{\boxed{\large{\bold{ \frac{x}{y}= \frac{168}{120} = \frac{7}{5} } } } }[/tex]
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