Math, asked by mashayelahmed, 6 months ago

PLEASE ANSWER!

The remainder when the expression x^3+9x^2+bx+c is divided by x-2 is twice the remainder when the expression is divided by x-1. Show that c=24

Given that x+8 is a factor of x^3+9x^2+bx+24, show that the equation x^3+9x^2+bx+24=0 has only one real root.

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Answered by rajeshkumarsinghb

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I can't understand what you are writing

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