Question

Please answer :

The sum of the digits of a three-digit number is 16. The tens digit is one less than the
hundreds digit and the ones digit is half the tens digit. If the digits are reversed, the
number decreases by 396. Find the number.​

Answer 1

Answer:

763.

Step-by-step explanation:

hundreds digit = X

tens digit = y

ones digit = z

x+y+z = 16 ------(1)

y= x-1

so, X = y+1 = -----(2)

z= 0.5y ------ (3)

substituting EQ (2) and EQ (3) in EQ (1) :

y+1+y+0.5y = 16

2.5y = 15

so, y = 6

X= 7

z = 3

so, the number = 763.

the number reversed = 367

Difference = 763-367= 396 {shown}.

Answer 2

Answer:

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