please answer :
The velocity of a body of mass 100g increases from m/s to 10 m/s on application of constant force for 2s
i)what is the momentum of body before the force starts acting?
ii)what is the momentum of the body 2s after force starts acting?
iii)what is the change in momentum of body in 2s interval?
iv)what is the value of the constant force acting on body?
v)what will be the velocity of body 1s after application of force
Answers
Answer:
Initial velocity (u) = 4 m/s
Final velocity (v) = 8 m/s
Mass (m) = 10 kg
Time (t) = 2 seconds
Initial momentum (p₁) = m × u
Final momentum (p₂) = m × v
(a)
Momentum before the force act = Initial momentum
= m × u
= 10 × 4
= 40 kg.m/s
(b)
Momentum after the force act = Final momentum
= m × v
= 10 × 8
= 80 kg.m/s
(c)
Momentum gain = Final momentum - Initial momentum
= 80 - 40 = 40 kg.m/s
Momentum gain in momentum per second = Momentum gain / time
= 40 / 2 = 20 kg.m/s
(d)
Force = mass × acceleration
= m × (v - u) / t ( as, acceleration is change in velocity per time)
= 10 × (8 - 4) / 2
= 10 × 2
= 20 N
Explanation:
Answer:
20 n
is the correct answer