Question

Please answer these 2 attached questions.

Answer 1

Answer:

2)4s

3)24km/hr

Explanation:

_____________________________

_____________________________

2) given,

• Avg.velocity,

V=90km/hr

=90×(5/18)m/s

=25m/s

• distance,

S= 100m

_____________________________

velocity=distance/time

therefore,min.time=distance/velocity

t. =100/25

=4s

_____________________________

_____________________________

3) bike travels from A to B with one velocity (V1) and returns to B with another velocity(V2)

therefore, distance is same for both case.and we can use harmonic mean formula to find average speed.

$avg.velocity = \frac{2v1v2}{v1 + v2} \\ = \frac{2 \times 20 \times 30}{20 + 30} \\ = \frac{1200}{50} \\ = \frac{120}{5} \\ = 24$

(we can use this formula iff and only iff distances are same)

______________________________

______________________________

hope it helps..!!

Answer 2

Answer:4 sec

24 km /hr

Explanation:

Pls mark me brainlist