Please answer these and show work If they correct I'll mark you bainlist
Answers
4.
Given that: x² +6x+8
=x² +4x+2x+8, (split middle term)
=(x² +4x)+(2x+8), (group pair of terms)
=x(x+4)+2(x+4), (factor each binomials)
=(x+4)(x+2), (factor out common factor (x+4)
Hence factors of x² +6x+8 are (x+4)(x+2)
5.
Factor:4x2−4x−15
Factor by splitting the middle term.
Multiply the coefficient of the first term
(4) by the constant term
(−15) .
4×−15=−60
Find two factors of
−60 that add up to −4
. The numbers 6and −10 meet the requirement.
Split −4x as the sum of 6x and −10x .
4x2+6x−10x-15
Factor out the common term from the first two terms and the second two terms.
2x(2x+3)−5(2x+3)
Factor out the common term
(2x+3) .
(2x+3)(2x−5)
7.
4x²-20x-24
4x-12x-8x-24
4x(x-3) -8(x-3) =0
4x-8=0 x-3=0
4x=8 x=3
x=8÷4
x=3
x=2.
8.
9m²+12m-32
9m²=12m-32
9m²-12m+32=0
9m²-12m=32