Question

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Answer 1

Answer:

The combustion of CH4 and C2H4 can be given as:

CH4 + 2O2→ CO2 + 2H2O

C2H4 + 3O2→ 2CO2 + 2H2O

The total volume of the mixture = 50 ml

Volume of CH4 = 60 % of 50 ml = (60x50)/100 = 30 ml = 0.03 L

Volume of C2H4 = 40% of 50 ml = (40x50)/100 = 20ml = 0.02 L

We know that 1 mole of gas = 22.4 L of the gas.

According to the balanced chemical equation we can say that,

22.4 L of CH4 gives 22.4 L of CO2.

So, 0.03 L of CH4 will give (0.03 x 22.4) / 22.4 = 0.03 L of CO2.

Similarly,

22.4 L of C2H4 gives (2 x 22.4)L of CO2.

So, 0.02 L of C2H4 will give (2 x 22.4 x 0.02) / 22.4 = 0.04 L of CO2.

Total Volume of CO2 = 0.03 + 0.04 = 0.07 L = 70 ml