Question

please answer these its urgent​

Answer 1

Answer:

Step-by-step explanation:

We are given that ∆SQR ~∆RPQ so

Angle S = Angle R

Angle R = 102°

In ∆ SQR , by Angle sum property of triangle we can find Angle SRQ

Angle Q + Angle RSQ + Angle SRQ = 180°

51° + 102° + Angle SRQ = 180°

Angle SRQ = 180° –(51° + 102°)

Angle SRQ = 180° – 153°

Angle SRQ = 37°

Angle PRS = Angle PRQ – Angle SRQ

Angle PRS = 102° – 37°

Angle PRS = 65 °

Hence the answer is 65°

Hope this helps you

Answer 2

Answer:

If pqr similar to sqr

Therefore angle prq=angle qsr..... So angle qsr = 102 degrees.

Now angle srq = 27 degrees...

102 degrees - 27 degrees = 75 degrees... So option c is correct.