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13. (D)
(because sin²75°+cos²75°=1)
14. (B)
{Given, sec∅=x, cosec∅=y which implies that sin∅= 1/y then tan∅=sin∅.sec∅=x/y}
15. (D)
(if tan∅= 15/8 then by Pythagoras theorem cos∅=8/17)
16. (A)
{ since x=sec∅+tan∅ & y=sec∅-tan∅ then
xy= sec²∅-tan²∅=1}
17. (D)
{(sin∅+cos∅)²= sin²∅+cos²∅+2sin∅.cos∅}
18. (C)
(if tan∅= 1/√3 then ∅= 30° therefore,
cos2∅= cos2(30°)=cos60°=1/2)
19. (A)
(if sin∅=√3/2 then ∅= 60°)
20. (C)
(if ∅= 45° then (1-cos2(45°))/sin2(45°) = (1-cos90°)/sin90° = (1-0)/1= 1 Ans.)
21. (A)
22. (C)
(if tan(A+B)=1 then A+B= 45°)
23. (A)
(if cos(A-B)=√3/2 then A-B= 30°)
I hope it is helpful for uh
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