Question

please answer these
pre board 2017
1 will mark you as brainliest

Answer 1

in triangle ABC vs in triangle APM
angle B=angle M=90
Angle A is common angle
soABC~APM



coseca=p/h=CB/AC(in triangle ABC)=PM/PA*(in triangle APM)
CB/AC=PM/PA
=CA/PA=CB/PM



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Answer 2

Angle B = Angle M (90)
Angle A is common
Therefore ABC similar AMP