Math, asked by lohitha1, 1 year ago

please answer these quesion please its very urgent

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Answered by snehitha2
1
Hi friend!

Given,

PQ is a line
Ray OR is perpendicular to line PQ.
OS is another ray lying between rays OP and OR.
Need to prove : ∠ROS = ½ (∠QOS - ∠POS)

∠QOR = ∠POR = 90°

» ∠POS + ∠ROS = ∠POR
∠POS + ∠ROS = 90°
∠POS = 90° - ∠ROS ------(1)

» ∠QOS - ∠ROS = ∠QOR
∠QOS - ∠ROS = 90°
∠QOS = 90° + ∠ROS --------(2)

(2)-(1)

∠QOS - ∠POS = 90° + ∠ROS - (90° - ∠ROS)
∠QOS - ∠POS = 90° + ∠ROS - 90° + ∠ROS
∠QOS - ∠POS = 2∠ROS
2∠ROS = ∠QOS - ∠POS
∠ROS = ½(∠QOS - ∠POS)


Hence proved!

Hope it helps…

NETHUNITHU: thanks friend
NETHUNITHU: maths easy for u??
NETHUNITHU: u are math genious
NETHUNITHU: supeerrrrrr
lohitha1: yes
lohitha1: she is very perfect in maths
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